When a boy pulls his sled with a rope, the rope makes an angle of 35° with the horizontal. If a pull of 16 pounds on the rope is needed to move the sled, what is the horizontal component force? 9 lb 13 lb 19 lb 22 lb
Accepted Solution
A:
Answer: 13 lb Step-by-step explanation:The horizontal component of the force is the magnitude of the force multiplied by the cosine of the angle with the horizontal. (16 lb)·cos(35°) ≈ 13.1 lb ≈ 13 lb